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The issues: The cluster is still replicating data to the secondary even though it hasn't been updated in a while. We are using the default settings in SSMS. If I go into DBCC CHECKDB and run it with the default settings, it runs for hours (or even days) on full recovery - even though there are no changes. The solution: We tried updating our DPM object definition to a 30 second checkpoint, but it's still causing issues. Here is an example of the issues: Full Table Scan - UPDATE xxx SET Text = '123456789', Updated = GETDATE() I don't understand why this is happening. I've tried completely disabling the dumppartionhistory table, but that hasn't resolved the issue. Ideas? A: Finally identified the cause - I wasn't taking into consideration DR enabling the availability group. If you don't enable DR, it will keep the secondary up to date with the primary. United States Court of Appeals Fifth Circuit F I L E D IN THE UNITED STATES COURT OF APPEALS FOR THE FIFTH What's New In? Q: python enumerate() return index I am using the enumerate() to do some task. Basically, I want to know the position of the element in the enumerate(). Lets say I have the following: list = [1,2,3,4,5,6] def func1(list): list.pop(0) return list def func2(list): list.append('s') return list what I want to do is, say I want to use the enumerate() to do a simple task: def func_pre(list): j = 0 for i, e in enumerate(list): if e == func1(list)[j] or e == func2(list)[j]: j += 1 print i, e I found that I can do this. but the problem is that I want to get the index of the element, without using the index of i. How can I get the index of e? Is there any other way? A: The enumerate function returns pairs of elements and their indices. The first element is always the first item of the input sequence, and the second element is generally the element that you specified as the argument to enumerate. Thus, to get the index of the element from list1 which you are poping from list2, you can just do list1.index(item) on both lists (if item is the element you're trying to locate). The enumerate function is useful when you have multiple similar items and you don't want the overhead of making a copy of the sequence and repeatedly calling index to find each element. A: "Generic" answer, is something like this: def func_pre(list_a, list_b): # assume you want to return the data from list_a # and data from list_b that you are interested in # compute the indices from index to element a_indices = [i for i, e in enumerate(list_a) if e == func1(list System Requirements: Minimum System Requirements: CPU: Intel® Core™ i5-3570 (Turbo Boost up to 4.0 GHz, Quad-core) Intel® Core™ i5-3540 (Turbo Boost up to 3.9 GHz, Quad-core) Intel® Core™ i3-2320 (Turbo Boost up to 3.7 GHz, Quad-core) Intel® Core™ i3-2130 (Turbo Boost up to 3.6 GHz, Quad-core) Intel® Core™
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